push: split switch cases
We want all the cases that don't do anything with a branch first, and then the rest. That way we will be able to get the branch and die if there's a problem in the parent function, instead of inside the function of each mode. Signed-off-by: Felipe Contreras <felipe.contreras@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -254,11 +254,20 @@ static void setup_default_push_refspecs(struct remote *remote)
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int same_remote = is_same_remote(remote);
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switch (push_default) {
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default:
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case PUSH_DEFAULT_MATCHING:
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refspec_append(&rs, ":");
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return;
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case PUSH_DEFAULT_NOTHING:
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die(_("You didn't specify any refspecs to push, and "
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"push.default is \"nothing\"."));
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return;
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default:
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break;
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}
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switch (push_default) {
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default:
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case PUSH_DEFAULT_UNSPECIFIED:
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case PUSH_DEFAULT_SIMPLE:
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setup_push_simple(remote, branch, same_remote);
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@ -271,11 +280,6 @@ static void setup_default_push_refspecs(struct remote *remote)
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case PUSH_DEFAULT_CURRENT:
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setup_push_current(remote, branch);
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return;
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case PUSH_DEFAULT_NOTHING:
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die(_("You didn't specify any refspecs to push, and "
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"push.default is \"nothing\"."));
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return;
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}
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}
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