fsck: turn off save_commit_buffer
When parsing a commit, the default behavior is to stuff the original buffer into a commit_slab (which takes ownership of it). But for a tool like fsck, this isn't useful. While we may look at the buffer further as part of fsck_commit(), we'll always do so through a separate pointer; attaching the buffer to the slab doesn't help. Worse, it means we have to remember to free the commit buffer in all call paths. We do so in fsck_obj(), which covers a regular "git fsck". But with "--connectivity-only", we forget to do so in both traverse_one_object(), which covers reachable objects, and mark_unreachable_referents(), which covers unreachable ones. As a result, that mode ends up storing an uncompressed copy of every commit on the heap at once. We could teach the code paths for --connectivity-only to also free commit buffers. But there's an even easier fix: we can just turn off the save_commit_buffer flag, and then we won't attach them to the commits in the first place. This reduces the peak heap of running "git fsck --connectivity-only" in a clone of linux.git from ~2GB to ~1GB. According to massif, the remaining memory goes where you'd expect: the object structs themselves, the obj_hash containing them, and the delta base cache. Note that we'll leave the call to free commit buffers in fsck_obj() for now; it's not quite redundant because of a related bug that we'll fix in a subsequent commit. Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -853,6 +853,7 @@ int cmd_fsck(int argc, const char **argv, const char *prefix)
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errors_found = 0;
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read_replace_refs = 0;
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save_commit_buffer = 0;
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argc = parse_options(argc, argv, prefix, fsck_opts, fsck_usage, 0);
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