Make diffcore_std only can run once before a diff_flush
When file renames/copies detection is turned on, the second diffcore_std will degrade a 'C' pair to a 'R' pair. And this may happen when we run 'git log --follow' with hard copies finding. That is, the try_to_follow_renames() will run diffcore_std to find the copies, and then 'git log' will issue another diffcore_std, which will reduce 'src->rename_used' and recognize this copy as a rename. This is not what we want. So, I think we really don't need to run diffcore_std more than one time. Signed-off-by: Bo Yang <struggleyb.nku@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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1da6175d43
8
diff.c
8
diff.c
@ -3737,6 +3737,12 @@ void diffcore_fix_diff_index(struct diff_options *options)
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void diffcore_std(struct diff_options *options)
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{
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/* We never run this function more than one time, because the
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* rename/copy detection logic can only run once.
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*/
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if (diff_queued_diff.run)
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return;
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if (options->skip_stat_unmatch)
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diffcore_skip_stat_unmatch(options);
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if (options->break_opt != -1)
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@ -3756,6 +3762,8 @@ void diffcore_std(struct diff_options *options)
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DIFF_OPT_SET(options, HAS_CHANGES);
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else
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DIFF_OPT_CLR(options, HAS_CHANGES);
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diff_queued_diff.run = 1;
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}
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int diff_result_code(struct diff_options *opt, int status)
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@ -91,11 +91,13 @@ struct diff_queue_struct {
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struct diff_filepair **queue;
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int alloc;
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int nr;
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int run;
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};
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#define DIFF_QUEUE_CLEAR(q) \
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do { \
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(q)->queue = NULL; \
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(q)->nr = (q)->alloc = 0; \
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(q)->run = 0; \
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} while(0);
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extern struct diff_queue_struct diff_queued_diff;
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