grep: re-order rev-parsing loop

We loop over the arguments, but every branch of the loop
hits either a "continue" or a "break". Surely we can make
this simpler.

The final conditional is:

  if (arg is a rev) {
	  ... handle rev ...
	  continue;
  }
  break;

We can rewrite this as:

  if (arg is not a rev)
	  break;

  ... handle rev ...

That makes the flow a little bit simpler, and will make
things much easier to follow when we add more logic in
future patches.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2017-02-14 01:04:17 -05:00 committed by Junio C Hamano
parent dca3b5f5ce
commit 20d6421cae

View File

@ -1154,20 +1154,22 @@ int cmd_grep(int argc, const char **argv, const char *prefix)
const char *arg = argv[i];
unsigned char sha1[20];
struct object_context oc;
struct object *object;
if (!strcmp(arg, "--")) {
i++;
seen_dashdash = 1;
break;
}
/* Is it a rev? */
if (!get_sha1_with_context(arg, 0, sha1, &oc)) {
struct object *object = parse_object_or_die(sha1, arg);
/* Stop at the first non-rev */
if (get_sha1_with_context(arg, 0, sha1, &oc))
break;
object = parse_object_or_die(sha1, arg);
if (!seen_dashdash)
verify_non_filename(prefix, arg);
add_object_array_with_path(object, arg, &list, oc.mode, oc.path);
continue;
}
break;
}
/* The rest are paths */