strbuf_branchname: drop return value
The return value from strbuf_branchname() is confusing and useless: it's 0 if the whole name was consumed by an @-mark, but otherwise is the length of the original name we fed. No callers actually look at the return value, so let's just get rid of it. Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -1279,17 +1279,14 @@ int interpret_branch_name(const char *name, int namelen, struct strbuf *buf)
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return -1;
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}
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int strbuf_branchname(struct strbuf *sb, const char *name)
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void strbuf_branchname(struct strbuf *sb, const char *name)
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{
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int len = strlen(name);
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int used = interpret_branch_name(name, len, sb);
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if (used == len)
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return 0;
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if (used < 0)
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used = 0;
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strbuf_add(sb, name + used, len - used);
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return len;
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}
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int strbuf_check_branch_ref(struct strbuf *sb, const char *name)
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2
strbuf.h
2
strbuf.h
@ -562,7 +562,7 @@ static inline void strbuf_complete_line(struct strbuf *sb)
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strbuf_complete(sb, '\n');
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}
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extern int strbuf_branchname(struct strbuf *sb, const char *name);
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extern void strbuf_branchname(struct strbuf *sb, const char *name);
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extern int strbuf_check_branch_ref(struct strbuf *sb, const char *name);
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extern void strbuf_addstr_urlencode(struct strbuf *, const char *,
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