A loose object is not corrupt if it cannot be read due to EMFILE
"git fsck" bails out with a claim that a loose object that cannot be read but exists on the filesystem to be corrupt, which is wrong when read_object() failed due to e.g. EMFILE. Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -2090,16 +2090,21 @@ void *read_sha1_file_repl(const unsigned char *sha1,
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const unsigned char **replacement)
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const unsigned char **replacement)
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{
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{
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const unsigned char *repl = lookup_replace_object(sha1);
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const unsigned char *repl = lookup_replace_object(sha1);
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void *data = read_object(repl, type, size);
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void *data;
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char *path;
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char *path;
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const struct packed_git *p;
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const struct packed_git *p;
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errno = 0;
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data = read_object(repl, type, size);
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if (data) {
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if (data) {
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if (replacement)
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if (replacement)
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*replacement = repl;
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*replacement = repl;
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return data;
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return data;
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}
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}
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if (errno != ENOENT)
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die_errno("failed to read object %s", sha1_to_hex(sha1));
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/* die if we replaced an object with one that does not exist */
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/* die if we replaced an object with one that does not exist */
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if (repl != sha1)
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if (repl != sha1)
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die("replacement %s not found for %s",
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die("replacement %s not found for %s",
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