Return error when not checking out an entry due to dirtiness.
Without -f flag, 'git-checkout-index foo.c' issued an error message when foo.c already existed in the working tree and did not match index. However it did not return an error from the underlying checkout_entry() function and resulted in a successful exit(0). Signed-off-by: Junio C Hamano <junkio@cox.net>
This commit is contained in:
parent
64a2228b02
commit
4b12dae69a
@ -63,15 +63,20 @@ static int checkout_file(const char *name)
|
|||||||
|
|
||||||
static int checkout_all(void)
|
static int checkout_all(void)
|
||||||
{
|
{
|
||||||
int i;
|
int i, errs = 0;
|
||||||
|
|
||||||
for (i = 0; i < active_nr ; i++) {
|
for (i = 0; i < active_nr ; i++) {
|
||||||
struct cache_entry *ce = active_cache[i];
|
struct cache_entry *ce = active_cache[i];
|
||||||
if (ce_stage(ce))
|
if (ce_stage(ce))
|
||||||
continue;
|
continue;
|
||||||
if (checkout_entry(ce, &state) < 0)
|
if (checkout_entry(ce, &state) < 0)
|
||||||
return -1;
|
errs++;
|
||||||
}
|
}
|
||||||
|
if (errs)
|
||||||
|
/* we have already done our error reporting.
|
||||||
|
* exit with the same code as die().
|
||||||
|
*/
|
||||||
|
exit(128);
|
||||||
return 0;
|
return 0;
|
||||||
}
|
}
|
||||||
|
|
||||||
|
2
entry.c
2
entry.c
@ -132,7 +132,7 @@ int checkout_entry(struct cache_entry *ce, struct checkout *state)
|
|||||||
if (!state->force) {
|
if (!state->force) {
|
||||||
if (!state->quiet)
|
if (!state->quiet)
|
||||||
fprintf(stderr, "git-checkout-index: %s already exists\n", path);
|
fprintf(stderr, "git-checkout-index: %s already exists\n", path);
|
||||||
return 0;
|
return -1;
|
||||||
}
|
}
|
||||||
|
|
||||||
/*
|
/*
|
||||||
|
Loading…
Reference in New Issue
Block a user