push: reorganize setup_push_simple()
Simply move the code around and remove dead code. In particular the '!same_remote' conditional is a no-op since that part of the code is the same_remote leg of the conditional beforehand. No functional changes. Suggestions-by: Elijah Newren <newren@gmail.com> Signed-off-by: Felipe Contreras <felipe.contreras@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -225,13 +225,14 @@ static void setup_push_current(struct remote *remote, struct branch *branch)
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static void setup_push_simple(struct remote *remote, struct branch *branch, int same_remote)
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{
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const char *dst;
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if (!branch)
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die(_(message_detached_head_die), remote->name);
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if (!same_remote) {
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if (!branch)
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die(_(message_detached_head_die), remote->name);
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refspec_appendf(&rs, "%s:%s", branch->refname, branch->refname);
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dst = branch->refname;
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} else {
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if (!branch)
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die(_(message_detached_head_die), remote->name);
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if (!branch->merge_nr || !branch->merge || !branch->remote_name)
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die(_("The current branch %s has no upstream branch.\n"
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"To push the current branch and set the remote as upstream, use\n"
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@ -243,20 +244,14 @@ static void setup_push_simple(struct remote *remote, struct branch *branch, int
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if (branch->merge_nr != 1)
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die(_("The current branch %s has multiple upstream branches, "
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"refusing to push."), branch->name);
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if (!same_remote)
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die(_("You are pushing to remote '%s', which is not the upstream of\n"
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"your current branch '%s', without telling me what to push\n"
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"to update which remote branch."),
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remote->name, branch->name);
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if (1) {
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/* Additional safety */
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if (strcmp(branch->refname, branch->merge[0]->src))
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die_push_simple(branch, remote);
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}
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/* Additional safety */
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if (strcmp(branch->refname, branch->merge[0]->src))
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die_push_simple(branch, remote);
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refspec_appendf(&rs, "%s:%s", branch->refname, branch->merge[0]->src);
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dst = branch->merge[0]->src;
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}
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refspec_appendf(&rs, "%s:%s", branch->refname, dst);
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}
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static int is_same_remote(struct remote *remote)
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