parse_color: drop COLOR_BACKGROUND macro
Commit695d95d
(parse_color: refactor color storage, 2014-11-20) introduced two macros, COLOR_FOREGROUND and COLOR_BACKGROUND. The latter conflicts with a system macro defined on Windows, breaking compilation there. The simplest solution is to just get rid of these macros entirely. They are constants that are only used in one place (since the whole point of695d95d
was to avoid repeating ourselves). Their main function is to make the magic character constants more readable, but we can do the same thing with a comment. Reported-by: Johannes Sixt <j6t@kdbg.org> Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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9
color.c
9
color.c
@ -144,9 +144,6 @@ int color_parse(const char *value, char *dst)
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return color_parse_mem(value, strlen(value), dst);
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}
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#define COLOR_FOREGROUND '3'
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#define COLOR_BACKGROUND '4'
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/*
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* Write the ANSI color codes for "c" to "out"; the string should
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* already have the ANSI escape code in it. "out" should have enough
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@ -245,12 +242,14 @@ int color_parse_mem(const char *value, int value_len, char *dst)
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if (!color_empty(&fg)) {
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if (sep++)
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*dst++ = ';';
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dst = color_output(dst, &fg, COLOR_FOREGROUND);
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/* foreground colors are all in the 3x range */
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dst = color_output(dst, &fg, '3');
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}
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if (!color_empty(&bg)) {
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if (sep++)
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*dst++ = ';';
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dst = color_output(dst, &bg, COLOR_BACKGROUND);
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/* background colors are all in the 4x range */
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dst = color_output(dst, &bg, '4');
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}
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*dst++ = 'm';
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}
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