parse_date_basic(): return early when given a bogus timestamp
When the input does not have GMT timezone offset, the code computes it by computing the local and GMT time for the given timestamp. But there is no point doing so if the given timestamp is known to be a bogus one. Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
parent
282616c72d
commit
7fcec48da9
6
date.c
6
date.c
@ -696,6 +696,9 @@ int parse_date_basic(const char *date, unsigned long *timestamp, int *offset)
|
||||
|
||||
/* mktime uses local timezone */
|
||||
*timestamp = tm_to_time_t(&tm);
|
||||
if (*timestamp == -1)
|
||||
return -1;
|
||||
|
||||
if (*offset == -1) {
|
||||
time_t temp_time = mktime(&tm);
|
||||
if ((time_t)*timestamp > temp_time) {
|
||||
@ -705,9 +708,6 @@ int parse_date_basic(const char *date, unsigned long *timestamp, int *offset)
|
||||
}
|
||||
}
|
||||
|
||||
if (*timestamp == -1)
|
||||
return -1;
|
||||
|
||||
if (!tm_gmt)
|
||||
*timestamp -= *offset * 60;
|
||||
return 0; /* success */
|
||||
|
Loading…
Reference in New Issue
Block a user