Merge branch 'jh/unpack-trees-micro-optim'
In a 2- and 3-way merge of trees, more than one source trees often end up sharing an identical subtree; optimize by not reading the same tree multiple times in such a case. * jh/unpack-trees-micro-optim: unpack-trees: avoid duplicate ODB lookups during checkout
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commit
8868ba1962
@ -604,12 +604,18 @@ static int switch_cache_bottom(struct traverse_info *info)
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return ret;
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}
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static inline int are_same_oid(struct name_entry *name_j, struct name_entry *name_k)
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{
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return name_j->oid && name_k->oid && !oidcmp(name_j->oid, name_k->oid);
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}
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static int traverse_trees_recursive(int n, unsigned long dirmask,
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unsigned long df_conflicts,
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struct name_entry *names,
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struct traverse_info *info)
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{
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int i, ret, bottom;
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int nr_buf = 0;
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struct tree_desc t[MAX_UNPACK_TREES];
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void *buf[MAX_UNPACK_TREES];
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struct traverse_info newinfo;
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@ -626,18 +632,40 @@ static int traverse_trees_recursive(int n, unsigned long dirmask,
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newinfo.pathlen += tree_entry_len(p) + 1;
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newinfo.df_conflicts |= df_conflicts;
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/*
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* Fetch the tree from the ODB for each peer directory in the
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* n commits.
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*
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* For 2- and 3-way traversals, we try to avoid hitting the
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* ODB twice for the same OID. This should yield a nice speed
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* up in checkouts and merges when the commits are similar.
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*
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* We don't bother doing the full O(n^2) search for larger n,
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* because wider traversals don't happen that often and we
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* avoid the search setup.
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*
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* When 2 peer OIDs are the same, we just copy the tree
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* descriptor data. This implicitly borrows the buffer
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* data from the earlier cell.
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*/
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for (i = 0; i < n; i++, dirmask >>= 1) {
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const unsigned char *sha1 = NULL;
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if (dirmask & 1)
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sha1 = names[i].oid->hash;
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buf[i] = fill_tree_descriptor(t+i, sha1);
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if (i > 0 && are_same_oid(&names[i], &names[i - 1]))
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t[i] = t[i - 1];
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else if (i > 1 && are_same_oid(&names[i], &names[i - 2]))
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t[i] = t[i - 2];
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else {
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const unsigned char *sha1 = NULL;
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if (dirmask & 1)
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sha1 = names[i].oid->hash;
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buf[nr_buf++] = fill_tree_descriptor(t+i, sha1);
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}
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}
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bottom = switch_cache_bottom(&newinfo);
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ret = traverse_trees(n, t, &newinfo);
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restore_cache_bottom(&newinfo, bottom);
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for (i = 0; i < n; i++)
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for (i = 0; i < nr_buf; i++)
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free(buf[i]);
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return ret;
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