line-log: suppress diff output with "-s"

When "-L" is in use, we ignore any diff output format that the user
provides to us, and just always print a patch (with extra context lines
covering the whole area of interest). It's not entirely clear what we
should do with all formats (e.g., should "--stat" show just the diffstat
of the touched lines, or the stat for the whole file?).

But "-s" is pretty clear: the user probably wants to see just the
commits that touched those lines, without any diff at all. Let's at
least make that work.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2019-03-07 14:45:15 -05:00 committed by Junio C Hamano
parent 36eb1cb9cf
commit 9f607cd09c
2 changed files with 11 additions and 2 deletions

View File

@ -1103,10 +1103,12 @@ static int process_all_files(struct line_log_data **range_out,
int line_log_print(struct rev_info *rev, struct commit *commit)
{
struct line_log_data *range = lookup_line_range(rev, commit);
show_log(rev);
dump_diff_hacky(rev, range);
if (!(rev->diffopt.output_format & DIFF_FORMAT_NO_OUTPUT)) {
struct line_log_data *range = lookup_line_range(rev, commit);
dump_diff_hacky(rev, range);
}
return 1;
}

View File

@ -115,4 +115,11 @@ test_expect_success 'range_set_union' '
git log $(for x in $(test_seq 200); do echo -L $((2*x)),+1:c.c; done)
'
test_expect_success '-s shows only line-log commits' '
git log --format="commit %s" -L1,24:b.c >expect.raw &&
grep ^commit expect.raw >expect &&
git log --format="commit %s" -L1,24:b.c -s >actual &&
test_cmp expect actual
'
test_done