get_sha1_with_context: always initialize oc->symlink_path
The get_sha1_with_context() function zeroes out the oc->symlink_path strbuf, but doesn't use strbuf_init() to set up the usual invariants (like pointing to the slopbuf). We don't actually write to the oc->symlink_path strbuf unless we call get_tree_entry_follow_symlinks(), and that function does initialize it. However, readers may still look at the zero'd strbuf. In practice this isn't a triggerable bug. The only caller that looks at it only does so when the mode we found is 0. This doesn't happen for non-tree-entries (where we return S_IFINVALID). A broken tree entry could have a mode of 0, but canon_mode() quietly rewrites that into S_IFGITLINK. So the "0" mode should only come up when we did indeed find a symlink. This is mostly just an accident of how the code happens to work, though. Let's future-proof ourselves to make sure the strbuf is properly initialized for all calls (it's only a few struct member assignments, not a heap allocation). Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -1511,6 +1511,7 @@ static int get_sha1_with_context_1(const char *name,
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memset(oc, 0, sizeof(*oc));
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oc->mode = S_IFINVALID;
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strbuf_init(&oc->symlink_path, 0);
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ret = get_sha1_1(name, namelen, sha1, flags);
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if (!ret)
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return ret;
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@ -589,7 +589,6 @@ enum follow_symlinks_result get_tree_entry_follow_symlinks(unsigned char *tree_s
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int i;
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init_tree_desc(&t, NULL, 0UL);
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strbuf_init(result_path, 0);
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strbuf_addstr(&namebuf, name);
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hashcpy(current_tree_sha1, tree_sha1);
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