interpret_branch_name: rename "cp" variable to "at"
In the original version of this function, "cp" acted as a pointer to many different things. Since the refactoring in the last patch, it only marks the at-sign in the string. Let's use a more descriptive variable name. Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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a39c14af82
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10
sha1_name.c
10
sha1_name.c
@ -1119,7 +1119,7 @@ static int interpret_upstream_mark(const char *name, int namelen,
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*/
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*/
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int interpret_branch_name(const char *name, int namelen, struct strbuf *buf)
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int interpret_branch_name(const char *name, int namelen, struct strbuf *buf)
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{
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{
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char *cp;
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char *at;
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int len = interpret_nth_prior_checkout(name, buf);
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int len = interpret_nth_prior_checkout(name, buf);
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if (!namelen)
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if (!namelen)
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@ -1134,15 +1134,15 @@ int interpret_branch_name(const char *name, int namelen, struct strbuf *buf)
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return reinterpret(name, namelen, len, buf);
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return reinterpret(name, namelen, len, buf);
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}
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}
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cp = strchr(name, '@');
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at = strchr(name, '@');
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if (!cp)
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if (!at)
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return -1;
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return -1;
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len = interpret_empty_at(name, namelen, cp - name, buf);
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len = interpret_empty_at(name, namelen, at - name, buf);
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if (len > 0)
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if (len > 0)
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return reinterpret(name, namelen, len, buf);
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return reinterpret(name, namelen, len, buf);
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len = interpret_upstream_mark(name, namelen, cp - name, buf);
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len = interpret_upstream_mark(name, namelen, at - name, buf);
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if (len > 0)
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if (len > 0)
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return len;
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return len;
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