1cf93847c1
8d96e7288f (t4034: bulk verify builtin word regex sanity, 2010-12-18)
added many tests with the intent to verify that operators consisting of
more than one symbol are kept together. These are tested by probing a
transition from, e.g., a!=b to x!=y, which results in the word-diff
[-a-]{+x+}!=[-b-]{+y+}
But that proves only that the letters and operators are separate tokens.
To prove that != is an unseparable token, we have to probe a transition
from, e.g., a=b to a!=b having a word-diff
a[-=-]{+!=+}b
that proves that the ! is not separate from the =.
In the post-image, add to or remove from operators a character that
turns it into another valid operator.
Change the identifiers used around operators such that the diff
algorithm does not have an incentive to match, e.g., a<b in one spot
in the pre-image with a<b elsewhere in the post-image.
Adjust the expected output to match the new differences. Notice that
there are some undesirable tokenizations around e, ., and -. This will
be addressed in a later change.
Signed-off-by: Johannes Sixt <j6t@kdbg.org>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
17 lines
267 B
Plaintext
17 lines
267 B
Plaintext
Foo() : x(0&42) { bar(x); }
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cout<<"Hello World?\n"<<endl;
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(1) (-1e10) (0xabcdef) 'y'
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[a] b->*v d.*e
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~!a !~b c+ d- e**f g&&h
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a*=b c/=d e%=f
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a++b c--d
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a<<=b c>>=d
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a<=b c<d e>=f g>h
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a!=b c=d
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a^=b c|=d e&=f
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a|b
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a?:b
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a==b c+d e-f g*h i/j k%l m<<n o>>p q&r s^t u|v
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a,b
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a:b
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