1cf93847c1
8d96e7288f (t4034: bulk verify builtin word regex sanity, 2010-12-18)
added many tests with the intent to verify that operators consisting of
more than one symbol are kept together. These are tested by probing a
transition from, e.g., a!=b to x!=y, which results in the word-diff
[-a-]{+x+}!=[-b-]{+y+}
But that proves only that the letters and operators are separate tokens.
To prove that != is an unseparable token, we have to probe a transition
from, e.g., a=b to a!=b having a word-diff
a[-=-]{+!=+}b
that proves that the ! is not separate from the =.
In the post-image, add to or remove from operators a character that
turns it into another valid operator.
Change the identifiers used around operators such that the diff
algorithm does not have an incentive to match, e.g., a<b in one spot
in the pre-image with a<b elsewhere in the post-image.
Adjust the expected output to match the new differences. Notice that
there are some undesirable tokenizations around e, ., and -. This will
be addressed in a later change.
Signed-off-by: Johannes Sixt <j6t@kdbg.org>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
17 lines
247 B
Plaintext
17 lines
247 B
Plaintext
Foo():x(0&&1){}
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cout<<"Hello World!\n"<<endl;
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1 -1e10 0xabcdef 'x'
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[a] b->v d.e
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!a ~b c++ d-- e*f g&h
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a*b c/d e%f
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a+b c-d
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a<<b c>>d
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a<b c<=d e>f g>=h
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a==b c!=d
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a^b c|d e&&f
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a||b
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a?b
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a=b c+=d e-=f g*=h i/=j k%=l m<<=n o>>=p q&=r s^=t u|=v
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a,b
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a::b
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